Java class inheritance and method overriding

class inheritance

A Java class can inherit from one other class. What a ‘child’ class inherits from its ‘parent’ class is all of the parent’s fields and methods:

class Mammal {
    int age;
    float weight;

    void eat() {
        // ...

    void sleep() {
        // ...

// 'Cat' inherits from 'Mammal'
class Cat extends Mammal {
    int lives;

    void meow() {
        // ...

The Cat class extends (inherits from) Mammal, so in addition to its own lives field and meow method, it also has age and weight fields as well as eat and sleep methods. In short, a child class has everything its parent does plus more.

If a class does not explicitly extend another, it implicitly extends a special built-in class called Object. A child class can have its own children, and thus classes in Java form a hierarchy with Object at the root. All classes are descendents of Object. This Object class contains several methods, which we’ll discuss later.

Because a descendent has everything which its ancestors have, the compiler accepts a descendent as a valid substitute for an ancestor:

Mammal m = new Cat();

Above, we can assign a Cat to a Mammal variable because a Cat is guaranteed to have all of the fields and all of the methods of a Mammal. However, we can only access the fields and methods of Mammal via the m variable:

Mammal m = new Cat();;                  // ok
m.meow();                 // compile error: 'Mammal' has no method 'meow'

You’d think the compiler should be able to figure out what type of instance the variable m references. Well, in this case it could, but in other cases it couldn’t:

Mammal m = new Cat();
if (x < 3) {
    m = new Dog();
m.meow();                 // depending on value of 'x', 'm' here might reference a 'Dog' rather than a 'Cat'

Because of such cases (which are very common), the compiler doesn’t presume to know the type of the referenced instance at any point.

This rule that descendents can substitute for their ancestors applies when we pass arguments to a method or return values from a method:

Having substituted a Cat for a Mammal, we can only get the Cat instance as a Cat again by casting. Such a ‘downcast’ performs a type check at runtime, throwing an exception if the check fails:

Mammal m = new Cat();
Cat c = (Cat) m;          // type check at runtime passes ('m' references a 'Cat')
c.meow();                 // ok
m = new Mammal();
c = (Cat) m;              // exception: type check at runtime fails ('m' references a 'Mammal')

Be clear that a downcast does not produce a new instance:

In other words, the compiler accepts our claim that this Mammal is actually a Cat, but this claim is checked when the downcast is executed.

method overriding

If a child class defines a method foo while inheriting a method foo with different parameter types, then foo is simply overloaded in the child class: the two methods just happen to have the same name, but otherwise have no necessary relation.

However, if a child class defines a method foo while inheriting a method foo with the same parameter types, then foo is overridden. When we call a method that has been overridden, the method to call may be partly determined at runtime when execution reaches the call:

// assume 'Cat' overrides 'eat' from 'Mammal'
Mammal m = new Mammal();;                        // call 'eat' of 'Mammal'
m = new Cat();;                        // call 'eat' of 'Cat'

Above, which eat gets called depends upon what type of instance m references at the time of the call: when m references a Mammal instance, the call invokes eat of Mammal; when m references a Cat instance, the call invokes eat of Cat.

Now imagine we have a class A which extends B, which extends C, which extends D, which extends E:

In short, which override gets invoked depends at runtime on the type of the actual instance. Each type either defines its own override, or it inherits the last override up the chain of inheritance.

Sometimes the compiler can determine which override to call, but sometimes the decision has to be left until the call is actually made at runtime:

A a;
B b;
C c;
D d;
E e;
// ... the above variables get initialized;                      // compiler knows this can only call 'foo' of 'B';                      // compiler knows this can only call 'foo' of 'B';                      // compiler cannot know whether to call 'foo' of 'B' or of 'E';                      // compiler cannot know whether to call 'foo' of 'B' or of 'E';                      // compiler cannot know whether to call 'foo' of 'B' or of 'E'

Above, variables of types A and B can only reference instances with method foo of B. The variables of types C, D, and E might reference instances with method foo of B, but they also might reference instances with method foo of E. So for the last three calls, the compiler can narrow down the choices to two methods, but the final decision between the two is made only when execution reaches the call at runtime.

Be careful not to confuse overriding and overloading! Overloads are separate methods that just happen to have the same name. The compiler always decides which overload a call refers to at compile time.